3(y+2)-2(y+1)=2

Solution for 3(y+2)-2(y+1)=2 equation:

Simplifying
3(y + 2) + -2(y + 1) = 2

Reorder the terms:
3(2 + y) + -2(y + 1) = 2
(2 * 3 + y * 3) + -2(y + 1) = 2
(6 + 3y) + -2(y + 1) = 2

Reorder the terms:
6 + 3y + -2(1 + y) = 2
6 + 3y + (1 * -2 + y * -2) = 2
6 + 3y + (-2 + -2y) = 2

Reorder the terms:
6 + -2 + 3y + -2y = 2

Combine like terms: 6 + -2 = 4
4 + 3y + -2y = 2

Combine like terms: 3y + -2y = 1y
4 + 1y = 2

Solving
4 + 1y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 1y = 2 + -4

Combine like terms: 4 + -4 = 0
0 + 1y = 2 + -4
1y = 2 + -4

Combine like terms: 2 + -4 = -2
1y = -2

Divide each side by '1'.
y = -2

Simplifying
y = -2