3(y+2)-4(y-3)=12

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Solution for 3(y+2)-4(y-3)=12 equation: 



3(y+2)-4(y-3)=12

We move all terms to the left:

3(y+2)-4(y-3)-(12)=0

We multiply parentheses

3y-4y+6+12-12=0

We add all the numbers together, and all the variables

-1y+6=0

We move all terms containing y to the left, all other terms to the right

-y=-6

y=-6/-1

y=+6

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