3(y+2)-6(y-2)=9y+18-12y

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Solution for 3(y+2)-6(y-2)=9y+18-12y equation: 



3(y+2)-6(y-2)=9y+18-12y

We move all terms to the left:

3(y+2)-6(y-2)-(9y+18-12y)=0

We add all the numbers together, and all the variables

3(y+2)-6(y-2)-(-3y+18)=0

We multiply parentheses

3y-6y-(-3y+18)+6+12=0

We get rid of parentheses

3y-6y+3y-18+6+12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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