3(y+2)-y=-2(y-1)+5

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Solution for 3(y+2)-y=-2(y-1)+5 equation: 



3(y+2)-y=-2(y-1)+5

We move all terms to the left:

3(y+2)-y-(-2(y-1)+5)=0

We add all the numbers together, and all the variables

-1y+3(y+2)-(-2(y-1)+5)=0

We multiply parentheses

-1y+3y-(-2(y-1)+5)+6=0



We calculate terms in parentheses: -(-2(y-1)+5), so:

-2(y-1)+5

We multiply parentheses

-2y+2+5

We add all the numbers together, and all the variables

-2y+7

Back to the equation:

-(-2y+7)



We add all the numbers together, and all the variables

2y-(-2y+7)+6=0

We get rid of parentheses

2y+2y-7+6=0

We add all the numbers together, and all the variables

4y-1=0

We move all terms containing y to the left, all other terms to the right

4y=1

y=1/4

y=1/4

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