3(y+2)4=5(y-1)+y

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Solution for 3(y+2)4=5(y-1)+y equation: 



3(y+2)4=5(y-1)+y

We move all terms to the left:

3(y+2)4-(5(y-1)+y)=0

We multiply parentheses

12y-(5(y-1)+y)+24=0



We calculate terms in parentheses: -(5(y-1)+y), so:

5(y-1)+y

We add all the numbers together, and all the variables

y+5(y-1)

We multiply parentheses

y+5y-5

We add all the numbers together, and all the variables

6y-5

Back to the equation:

-(6y-5)



We get rid of parentheses

12y-6y+5+24=0

We add all the numbers together, and all the variables

6y+29=0

We move all terms containing y to the left, all other terms to the right

6y=-29

y=-29/6

y=-4+5/6

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