3(y+2)=-(6y+48)

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Solution for 3(y+2)=-(6y+48) equation: 



3(y+2)=-(6y+48)

We move all terms to the left:

3(y+2)-(-(6y+48))=0

We multiply parentheses

3y-(-(6y+48))+6=0



We calculate terms in parentheses: -(-(6y+48)), so:

-(6y+48)

We get rid of parentheses

-6y-48

Back to the equation:

-(-6y-48)



We get rid of parentheses

3y+6y+48+6=0

We add all the numbers together, and all the variables

9y+54=0

We move all terms containing y to the left, all other terms to the right

9y=-54

y=-54/9

y=-6

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