3(y+2)=-2(y-1)

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Solution for 3(y+2)=-2(y-1) equation: 



3(y+2)=-2(y-1)

We move all terms to the left:

3(y+2)-(-2(y-1))=0

We multiply parentheses

3y-(-2(y-1))+6=0



We calculate terms in parentheses: -(-2(y-1)), so:

-2(y-1)

We multiply parentheses

-2y+2

Back to the equation:

-(-2y+2)



We get rid of parentheses

3y+2y-2+6=0

We add all the numbers together, and all the variables

5y+4=0

We move all terms containing y to the left, all other terms to the right

5y=-4

y=-4/5

y=-4/5

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