3(y+2)=-2(y-1)

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Solution for 3(y+2)=-2(y-1) equation:



3(y+2)=-2(y-1)
We move all terms to the left:
3(y+2)-(-2(y-1))=0
We multiply parentheses
3y-(-2(y-1))+6=0
We calculate terms in parentheses: -(-2(y-1)), so:
-2(y-1)
We multiply parentheses
-2y+2
Back to the equation:
-(-2y+2)
We get rid of parentheses
3y+2y-2+6=0
We add all the numbers together, and all the variables
5y+4=0
We move all terms containing y to the left, all other terms to the right
5y=-4
y=-4/5
y=-4/5

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