3(y+2)=-2(y-2)

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Solution for 3(y+2)=-2(y-2) equation: 



3(y+2)=-2(y-2)

We move all terms to the left:

3(y+2)-(-2(y-2))=0

We multiply parentheses

3y-(-2(y-2))+6=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We get rid of parentheses

3y+2y-4+6=0

We add all the numbers together, and all the variables

5y+2=0

We move all terms containing y to the left, all other terms to the right

5y=-2

y=-2/5

y=-2/5

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