3(y+2)=-2(y-4)

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Solution for 3(y+2)=-2(y-4) equation: 



3(y+2)=-2(y-4)

We move all terms to the left:

3(y+2)-(-2(y-4))=0

We multiply parentheses

3y-(-2(y-4))+6=0



We calculate terms in parentheses: -(-2(y-4)), so:

-2(y-4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We get rid of parentheses

3y+2y-8+6=0

We add all the numbers together, and all the variables

5y-2=0

We move all terms containing y to the left, all other terms to the right

5y=2

y=2/5

y=2/5

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