3(y+2)=-30

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Solution for 3(y+2)=-30 equation:



3(y+2)=-30
We move all terms to the left:
3(y+2)-(-30)=0
We add all the numbers together, and all the variables
3(y+2)+30=0
We multiply parentheses
3y+6+30=0
We add all the numbers together, and all the variables
3y+36=0
We move all terms containing y to the left, all other terms to the right
3y=-36
y=-36/3
y=-12

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