3(y+2)=2(2y-7)+y

Solution for 3(y+2)=2(2y-7)+y equation:

3(y+2)=2(2y-7)+y

We move all terms to the left:

3(y+2)-(2(2y-7)+y)=0

We multiply parentheses

3y-(2(2y-7)+y)+6=0


We calculate terms in parentheses: -(2(2y-7)+y), so:

2(2y-7)+y

We add all the numbers together, and all the variables

y+2(2y-7)

We multiply parentheses

y+4y-14

We add all the numbers together, and all the variables

5y-14

Back to the equation:

-(5y-14)


We get rid of parentheses

3y-5y+14+6=0

We add all the numbers together, and all the variables

-2y+20=0

We move all terms containing y to the left, all other terms to the right

-2y=-20

y=-20/-2

y=+10