3(y+2)=2(4y-5)+7

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Solution for 3(y+2)=2(4y-5)+7 equation: 



3(y+2)=2(4y-5)+7

We move all terms to the left:

3(y+2)-(2(4y-5)+7)=0

We multiply parentheses

3y-(2(4y-5)+7)+6=0



We calculate terms in parentheses: -(2(4y-5)+7), so:

2(4y-5)+7

We multiply parentheses

8y-10+7

We add all the numbers together, and all the variables

8y-3

Back to the equation:

-(8y-3)



We get rid of parentheses

3y-8y+3+6=0

We add all the numbers together, and all the variables

-5y+9=0

We move all terms containing y to the left, all other terms to the right

-5y=-9

y=-9/-5

y=1+4/5

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