3(y+2)=2(y+2)

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Solution for 3(y+2)=2(y+2) equation: 



3(y+2)=2(y+2)

We move all terms to the left:

3(y+2)-(2(y+2))=0

We multiply parentheses

3y-(2(y+2))+6=0



We calculate terms in parentheses: -(2(y+2)), so:

2(y+2)

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)



We get rid of parentheses

3y-2y-4+6=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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