3(y+2)=2(y+6)+7

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Solution for 3(y+2)=2(y+6)+7 equation: 



3(y+2)=2(y+6)+7

We move all terms to the left:

3(y+2)-(2(y+6)+7)=0

We multiply parentheses

3y-(2(y+6)+7)+6=0



We calculate terms in parentheses: -(2(y+6)+7), so:

2(y+6)+7

We multiply parentheses

2y+12+7

We add all the numbers together, and all the variables

2y+19

Back to the equation:

-(2y+19)



We get rid of parentheses

3y-2y-19+6=0

We add all the numbers together, and all the variables

y-13=0

We move all terms containing y to the left, all other terms to the right

y=13

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