3(y+2)=2(y-3)=-15

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Solution for 3(y+2)=2(y-3)=-15 equation: 



3(y+2)=2(y-3)=-15

We move all terms to the left:

3(y+2)-(2(y-3))=0

We multiply parentheses

3y-(2(y-3))+6=0



We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)



We get rid of parentheses

3y-2y+6+6=0

We add all the numbers together, and all the variables

y+12=0

We move all terms containing y to the left, all other terms to the right

y=-12

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