3(y+2)=3(y+4)

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Solution for 3(y+2)=3(y+4) equation: 



3(y+2)=3(y+4)

We move all terms to the left:

3(y+2)-(3(y+4))=0

We multiply parentheses

3y-(3(y+4))+6=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We get rid of parentheses

3y-3y-12+6=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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