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3(y+2)=3(y-2)
We move all terms to the left:
3(y+2)-(3(y-2))=0
We multiply parentheses
3y-(3(y-2))+6=0
We calculate terms in parentheses: -(3(y-2)), so:We get rid of parentheses
3(y-2)
We multiply parentheses
3y-6
Back to the equation:
-(3y-6)
3y-3y+6+6=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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