3(y+2)=4(y-2)

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Solution for 3(y+2)=4(y-2) equation: 



3(y+2)=4(y-2)

We move all terms to the left:

3(y+2)-(4(y-2))=0

We multiply parentheses

3y-(4(y-2))+6=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We get rid of parentheses

3y-4y+8+6=0

We add all the numbers together, and all the variables

-1y+14=0

We move all terms containing y to the left, all other terms to the right

-y=-14

y=-14/-1

y=+14

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