3(y+2)=4(y-2)+3y

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Solution for 3(y+2)=4(y-2)+3y equation: 



3(y+2)=4(y-2)+3y

We move all terms to the left:

3(y+2)-(4(y-2)+3y)=0

We multiply parentheses

3y-(4(y-2)+3y)+6=0



We calculate terms in parentheses: -(4(y-2)+3y), so:

4(y-2)+3y

We add all the numbers together, and all the variables

3y+4(y-2)

We multiply parentheses

3y+4y-8

We add all the numbers together, and all the variables

7y-8

Back to the equation:

-(7y-8)



We get rid of parentheses

3y-7y+8+6=0

We add all the numbers together, and all the variables

-4y+14=0

We move all terms containing y to the left, all other terms to the right

-4y=-14

y=-14/-4

y=3+1/2

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