3(y+2)=4(y-4)

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Solution for 3(y+2)=4(y-4) equation: 


Simplifying
3(y + 2) = 4(y + -4)

Reorder the terms:
3(2 + y) = 4(y + -4)
(2 * 3 + y * 3) = 4(y + -4)
(6 + 3y) = 4(y + -4)

Reorder the terms:
6 + 3y = 4(-4 + y)
6 + 3y = (-4 * 4 + y * 4)
6 + 3y = (-16 + 4y)

Solving
6 + 3y = -16 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
6 + 3y + -4y = -16 + 4y + -4y

Combine like terms: 3y + -4y = -1y
6 + -1y = -16 + 4y + -4y

Combine like terms: 4y + -4y = 0
6 + -1y = -16 + 0
6 + -1y = -16

Add '-6' to each side of the equation.
6 + -6 + -1y = -16 + -6

Combine like terms: 6 + -6 = 0
0 + -1y = -16 + -6
-1y = -16 + -6

Combine like terms: -16 + -6 = -22
-1y = -22

Divide each side by '-1'.
y = 22

Simplifying
y = 22

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