3(y+2)=4y+1

Solution for 3(y+2)=4y+1 equation:

Simplifying
3(y + 2) = 4y + 1

Reorder the terms:
3(2 + y) = 4y + 1
(2 * 3 + y * 3) = 4y + 1
(6 + 3y) = 4y + 1

Reorder the terms:
6 + 3y = 1 + 4y

Solving
6 + 3y = 1 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
6 + 3y + -4y = 1 + 4y + -4y

Combine like terms: 3y + -4y = -1y
6 + -1y = 1 + 4y + -4y

Combine like terms: 4y + -4y = 0
6 + -1y = 1 + 0
6 + -1y = 1

Add '-6' to each side of the equation.
6 + -6 + -1y = 1 + -6

Combine like terms: 6 + -6 = 0
0 + -1y = 1 + -6
-1y = 1 + -6

Combine like terms: 1 + -6 = -5
-1y = -5

Divide each side by '-1'.
y = 5

Simplifying
y = 5