3(y+2)=6-y

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Solution for 3(y+2)=6-y equation: 



3(y+2)=6-y

We move all terms to the left:

3(y+2)-(6-y)=0

We add all the numbers together, and all the variables

3(y+2)-(-1y+6)=0

We multiply parentheses

3y-(-1y+6)+6=0

We get rid of parentheses

3y+1y-6+6=0

We add all the numbers together, and all the variables

4y=0

y=0/4

y=0

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