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3(y+2)=9(6-y)
We move all terms to the left:
3(y+2)-(9(6-y))=0
We add all the numbers together, and all the variables
3(y+2)-(9(-1y+6))=0
We multiply parentheses
3y-(9(-1y+6))+6=0
We calculate terms in parentheses: -(9(-1y+6)), so:We get rid of parentheses
9(-1y+6)
We multiply parentheses
-9y+54
Back to the equation:
-(-9y+54)
3y+9y-54+6=0
We add all the numbers together, and all the variables
12y-48=0
We move all terms containing y to the left, all other terms to the right
12y=48
y=48/12
y=4
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