3(y+3)+4y=16

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Solution for 3(y+3)+4y=16 equation: 



3(y+3)+4y=16

We move all terms to the left:

3(y+3)+4y-(16)=0

We add all the numbers together, and all the variables

4y+3(y+3)-16=0

We multiply parentheses

4y+3y+9-16=0

We add all the numbers together, and all the variables

7y-7=0

We move all terms containing y to the left, all other terms to the right

7y=7

y=7/7

y=1

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