3(y+3)+5y=4(2y+1)+5

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Solution for 3(y+3)+5y=4(2y+1)+5 equation: 


Simplifying
3(y + 3) + 5y = 4(2y + 1) + 5

Reorder the terms:
3(3 + y) + 5y = 4(2y + 1) + 5
(3 * 3 + y * 3) + 5y = 4(2y + 1) + 5
(9 + 3y) + 5y = 4(2y + 1) + 5

Combine like terms: 3y + 5y = 8y
9 + 8y = 4(2y + 1) + 5

Reorder the terms:
9 + 8y = 4(1 + 2y) + 5
9 + 8y = (1 * 4 + 2y * 4) + 5
9 + 8y = (4 + 8y) + 5

Reorder the terms:
9 + 8y = 4 + 5 + 8y

Combine like terms: 4 + 5 = 9
9 + 8y = 9 + 8y

Add '-9' to each side of the equation.
9 + -9 + 8y = 9 + -9 + 8y

Combine like terms: 9 + -9 = 0
0 + 8y = 9 + -9 + 8y
8y = 9 + -9 + 8y

Combine like terms: 9 + -9 = 0
8y = 0 + 8y
8y = 8y

Add '-8y' to each side of the equation.
8y + -8y = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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