3(y+3)+5y=4(2y+1+5

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Solution for 3(y+3)+5y=4(2y+1+5 equation: 



3(y+3)+5y=4(2y+1+5

We move all terms to the left:

3(y+3)+5y-(4(2y+1+5)=0

We add all the numbers together, and all the variables

3(y+3)+5y-(4(2y+6)=0

We add all the numbers together, and all the variables

5y+3(y+3)-(4(2y+6)=0

We multiply parentheses

5y+3y-(4(2y+6)+9=0

We add all the numbers together, and all the variables

8y-(4(2y+6)+9=0

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