3(y+3)+y=2(y+1)+3

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Solution for 3(y+3)+y=2(y+1)+3 equation: 



3(y+3)+y=2(y+1)+3

We move all terms to the left:

3(y+3)+y-(2(y+1)+3)=0

We add all the numbers together, and all the variables

y+3(y+3)-(2(y+1)+3)=0

We multiply parentheses

y+3y-(2(y+1)+3)+9=0



We calculate terms in parentheses: -(2(y+1)+3), so:

2(y+1)+3

We multiply parentheses

2y+2+3

We add all the numbers together, and all the variables

2y+5

Back to the equation:

-(2y+5)



We add all the numbers together, and all the variables

4y-(2y+5)+9=0

We get rid of parentheses

4y-2y-5+9=0

We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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