3(y+3)+y=2(y-1)+1

Solution for 3(y+3)+y=2(y-1)+1 equation:

3(y+3)+y=2(y-1)+1

We move all terms to the left:

3(y+3)+y-(2(y-1)+1)=0

We add all the numbers together, and all the variables

y+3(y+3)-(2(y-1)+1)=0

We multiply parentheses

y+3y-(2(y-1)+1)+9=0


We calculate terms in parentheses: -(2(y-1)+1), so:

2(y-1)+1

We multiply parentheses

2y-2+1

We add all the numbers together, and all the variables

2y-1

Back to the equation:

-(2y-1)


We add all the numbers together, and all the variables

4y-(2y-1)+9=0

We get rid of parentheses

4y-2y+1+9=0

We add all the numbers together, and all the variables

2y+10=0

We move all terms containing y to the left, all other terms to the right

2y=-10

y=-10/2

y=-5