3(y+3)+y=2(y-1)+9

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Solution for 3(y+3)+y=2(y-1)+9 equation: 



3(y+3)+y=2(y-1)+9

We move all terms to the left:

3(y+3)+y-(2(y-1)+9)=0

We add all the numbers together, and all the variables

y+3(y+3)-(2(y-1)+9)=0

We multiply parentheses

y+3y-(2(y-1)+9)+9=0



We calculate terms in parentheses: -(2(y-1)+9), so:

2(y-1)+9

We multiply parentheses

2y-2+9

We add all the numbers together, and all the variables

2y+7

Back to the equation:

-(2y+7)



We add all the numbers together, and all the variables

4y-(2y+7)+9=0

We get rid of parentheses

4y-2y-7+9=0

We add all the numbers together, and all the variables

2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1

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