3(y+3)+y=2(y-1)-2

Solution for 3(y+3)+y=2(y-1)-2 equation:

3(y+3)+y=2(y-1)-2

We move all terms to the left:

3(y+3)+y-(2(y-1)-2)=0

We add all the numbers together, and all the variables

y+3(y+3)-(2(y-1)-2)=0

We multiply parentheses

y+3y-(2(y-1)-2)+9=0


We calculate terms in parentheses: -(2(y-1)-2), so:

2(y-1)-2

We multiply parentheses

2y-2-2

We add all the numbers together, and all the variables

2y-4

Back to the equation:

-(2y-4)


We add all the numbers together, and all the variables

4y-(2y-4)+9=0

We get rid of parentheses

4y-2y+4+9=0

We add all the numbers together, and all the variables

2y+13=0

We move all terms containing y to the left, all other terms to the right

2y=-13

y=-13/2

y=-6+1/2