3(y+3)-2(2y-4)=17

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Solution for 3(y+3)-2(2y-4)=17 equation: 


Simplifying
3(y + 3) + -2(2y + -4) = 17

Reorder the terms:
3(3 + y) + -2(2y + -4) = 17
(3 * 3 + y * 3) + -2(2y + -4) = 17
(9 + 3y) + -2(2y + -4) = 17

Reorder the terms:
9 + 3y + -2(-4 + 2y) = 17
9 + 3y + (-4 * -2 + 2y * -2) = 17
9 + 3y + (8 + -4y) = 17

Reorder the terms:
9 + 8 + 3y + -4y = 17

Combine like terms: 9 + 8 = 17
17 + 3y + -4y = 17

Combine like terms: 3y + -4y = -1y
17 + -1y = 17

Add '-17' to each side of the equation.
17 + -17 + -1y = 17 + -17

Combine like terms: 17 + -17 = 0
0 + -1y = 17 + -17
-1y = 17 + -17

Combine like terms: 17 + -17 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0

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