3(y+3)-8(4y-9)=-29y+3

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Solution for 3(y+3)-8(4y-9)=-29y+3 equation:


Simplifying
3(y + 3) + -8(4y + -9) = -29y + 3

Reorder the terms:
3(3 + y) + -8(4y + -9) = -29y + 3
(3 * 3 + y * 3) + -8(4y + -9) = -29y + 3
(9 + 3y) + -8(4y + -9) = -29y + 3

Reorder the terms:
9 + 3y + -8(-9 + 4y) = -29y + 3
9 + 3y + (-9 * -8 + 4y * -8) = -29y + 3
9 + 3y + (72 + -32y) = -29y + 3

Reorder the terms:
9 + 72 + 3y + -32y = -29y + 3

Combine like terms: 9 + 72 = 81
81 + 3y + -32y = -29y + 3

Combine like terms: 3y + -32y = -29y
81 + -29y = -29y + 3

Reorder the terms:
81 + -29y = 3 + -29y

Add '29y' to each side of the equation.
81 + -29y + 29y = 3 + -29y + 29y

Combine like terms: -29y + 29y = 0
81 + 0 = 3 + -29y + 29y
81 = 3 + -29y + 29y

Combine like terms: -29y + 29y = 0
81 = 3 + 0
81 = 3

Solving
81 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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