3(y+3)/5=+2y+6

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Solution for 3(y+3)/5=+2y+6 equation: 



3(y+3)/5=+2y+6

We move all terms to the left:

3(y+3)/5-(+2y+6)=0

We add all the numbers together, and all the variables

3(y+3)/5-(2y+6)=0

We get rid of parentheses

3(y+3)/5-2y-6=0

We multiply all the terms by the denominator


3(y+3)-2y*5-6*5=0

We add all the numbers together, and all the variables

3(y+3)-2y*5-30=0

We multiply parentheses

3y-2y*5+9-30=0

Wy multiply elements

3y-10y+9-30=0

We add all the numbers together, and all the variables

-7y-21=0

We move all terms containing y to the left, all other terms to the right

-7y=21

y=21/-7

y=-3

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