3(y+3)=-7y+19

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Solution for 3(y+3)=-7y+19 equation: 



3(y+3)=-7y+19

We move all terms to the left:

3(y+3)-(-7y+19)=0

We multiply parentheses

3y-(-7y+19)+9=0

We get rid of parentheses

3y+7y-19+9=0

We add all the numbers together, and all the variables

10y-10=0

We move all terms containing y to the left, all other terms to the right

10y=10

y=10/10

y=1

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