3(y+3)=12(y-4)

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Solution for 3(y+3)=12(y-4) equation: 



3(y+3)=12(y-4)

We move all terms to the left:

3(y+3)-(12(y-4))=0

We multiply parentheses

3y-(12(y-4))+9=0



We calculate terms in parentheses: -(12(y-4)), so:

12(y-4)

We multiply parentheses

12y-48

Back to the equation:

-(12y-48)



We get rid of parentheses

3y-12y+48+9=0

We add all the numbers together, and all the variables

-9y+57=0

We move all terms containing y to the left, all other terms to the right

-9y=-57

y=-57/-9

y=6+1/3

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