3(y+3)=13y+39

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Solution for 3(y+3)=13y+39 equation: 



3(y+3)=13y+39

We move all terms to the left:

3(y+3)-(13y+39)=0

We multiply parentheses

3y-(13y+39)+9=0

We get rid of parentheses

3y-13y-39+9=0

We add all the numbers together, and all the variables

-10y-30=0

We move all terms containing y to the left, all other terms to the right

-10y=30

y=30/-10

y=-3

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