3(y+3)=8(y-2)

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Solution for 3(y+3)=8(y-2) equation: 



3(y+3)=8(y-2)

We move all terms to the left:

3(y+3)-(8(y-2))=0

We multiply parentheses

3y-(8(y-2))+9=0



We calculate terms in parentheses: -(8(y-2)), so:

8(y-2)

We multiply parentheses

8y-16

Back to the equation:

-(8y-16)



We get rid of parentheses

3y-8y+16+9=0

We add all the numbers together, and all the variables

-5y+25=0

We move all terms containing y to the left, all other terms to the right

-5y=-25

y=-25/-5

y=+5

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