3(y+3)=y+13

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Solution for 3(y+3)=y+13 equation: 



3(y+3)=y+13

We move all terms to the left:

3(y+3)-(y+13)=0

We multiply parentheses

3y-(y+13)+9=0

We get rid of parentheses

3y-y-13+9=0

We add all the numbers together, and all the variables

2y-4=0

We move all terms containing y to the left, all other terms to the right

2y=4

y=4/2

y=2

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