3(y+33)=3(4y+5)

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Solution for 3(y+33)=3(4y+5) equation:



3(y+33)=3(4y+5)
We move all terms to the left:
3(y+33)-(3(4y+5))=0
We multiply parentheses
3y-(3(4y+5))+99=0
We calculate terms in parentheses: -(3(4y+5)), so:
3(4y+5)
We multiply parentheses
12y+15
Back to the equation:
-(12y+15)
We get rid of parentheses
3y-12y-15+99=0
We add all the numbers together, and all the variables
-9y+84=0
We move all terms containing y to the left, all other terms to the right
-9y=-84
y=-84/-9
y=9+1/3

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