3(y+4)+2(2+2y)=y-6y+12-(-4)

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Solution for 3(y+4)+2(2+2y)=y-6y+12-(-4) equation: 



3(y+4)+2(2+2y)=y-6y+12-(-4)

We move all terms to the left:

3(y+4)+2(2+2y)-(y-6y+12-(-4))=0

We add all the numbers together, and all the variables

3(y+4)+2(2y+2)-(y-6y+12-(-4))=0

We multiply parentheses

3y+4y-(y-6y+12-(-4))+12+4=0



We calculate terms in parentheses: -(y-6y+12-(-4)), so:

y-6y+12-(-4)

We add all the numbers together, and all the variables

-5y+16

Back to the equation:

-(-5y+16)



We add all the numbers together, and all the variables

7y-(-5y+16)+16=0

We get rid of parentheses

7y+5y-16+16=0

We add all the numbers together, and all the variables

12y=0

y=0/12

y=0

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