3(y+4)+2(y-3)=36

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Solution for 3(y+4)+2(y-3)=36 equation:



3(y+4)+2(y-3)=36
We move all terms to the left:
3(y+4)+2(y-3)-(36)=0
We multiply parentheses
3y+2y+12-6-36=0
We add all the numbers together, and all the variables
5y-30=0
We move all terms containing y to the left, all other terms to the right
5y=30
y=30/5
y=6

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