3(y+4)+5=33

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Solution for 3(y+4)+5=33 equation:



3(y+4)+5=33
We move all terms to the left:
3(y+4)+5-(33)=0
We add all the numbers together, and all the variables
3(y+4)-28=0
We multiply parentheses
3y+12-28=0
We add all the numbers together, and all the variables
3y-16=0
We move all terms containing y to the left, all other terms to the right
3y=16
y=16/3
y=5+1/3

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