3(y+4)+y=2(y+5)-2

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Solution for 3(y+4)+y=2(y+5)-2 equation:



3(y+4)+y=2(y+5)-2
We move all terms to the left:
3(y+4)+y-(2(y+5)-2)=0
We add all the numbers together, and all the variables
y+3(y+4)-(2(y+5)-2)=0
We multiply parentheses
y+3y-(2(y+5)-2)+12=0
We calculate terms in parentheses: -(2(y+5)-2), so:
2(y+5)-2
We multiply parentheses
2y+10-2
We add all the numbers together, and all the variables
2y+8
Back to the equation:
-(2y+8)
We add all the numbers together, and all the variables
4y-(2y+8)+12=0
We get rid of parentheses
4y-2y-8+12=0
We add all the numbers together, and all the variables
2y+4=0
We move all terms containing y to the left, all other terms to the right
2y=-4
y=-4/2
y=-2

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