3(y+4)-2(3y-1)=10

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Solution for 3(y+4)-2(3y-1)=10 equation:



3(y+4)-2(3y-1)=10
We move all terms to the left:
3(y+4)-2(3y-1)-(10)=0
We multiply parentheses
3y-6y+12+2-10=0
We add all the numbers together, and all the variables
-3y+4=0
We move all terms containing y to the left, all other terms to the right
-3y=-4
y=-4/-3
y=1+1/3

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