3(y+4)-2(y-1)=10

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Solution for 3(y+4)-2(y-1)=10 equation: 



3(y+4)-2(y-1)=10

We move all terms to the left:

3(y+4)-2(y-1)-(10)=0

We multiply parentheses

3y-2y+12+2-10=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4

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