3(y+4)-2(y-1)=13

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Solution for 3(y+4)-2(y-1)=13 equation: 


Simplifying
3(y + 4) + -2(y + -1) = 13

Reorder the terms:
3(4 + y) + -2(y + -1) = 13
(4 * 3 + y * 3) + -2(y + -1) = 13
(12 + 3y) + -2(y + -1) = 13

Reorder the terms:
12 + 3y + -2(-1 + y) = 13
12 + 3y + (-1 * -2 + y * -2) = 13
12 + 3y + (2 + -2y) = 13

Reorder the terms:
12 + 2 + 3y + -2y = 13

Combine like terms: 12 + 2 = 14
14 + 3y + -2y = 13

Combine like terms: 3y + -2y = 1y
14 + 1y = 13

Solving
14 + 1y = 13

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 1y = 13 + -14

Combine like terms: 14 + -14 = 0
0 + 1y = 13 + -14
1y = 13 + -14

Combine like terms: 13 + -14 = -1
1y = -1

Divide each side by '1'.
y = -1

Simplifying
y = -1

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