3(y+4)-8y=2

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Solution for 3(y+4)-8y=2 equation: 



3(y+4)-8y=2

We move all terms to the left:

3(y+4)-8y-(2)=0

We add all the numbers together, and all the variables

-8y+3(y+4)-2=0

We multiply parentheses

-8y+3y+12-2=0

We add all the numbers together, and all the variables

-5y+10=0

We move all terms containing y to the left, all other terms to the right

-5y=-10

y=-10/-5

y=+2

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