3(y+4)/y-4=7

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Solution for 3(y+4)/y-4=7 equation: 



3(y+4)/y-4=7

We move all terms to the left:

3(y+4)/y-4-(7)=0



Domain of the equation: y!=0

y∈R



We add all the numbers together, and all the variables

3(y+4)/y-11=0

We multiply all the terms by the denominator


3(y+4)-11*y=0

We add all the numbers together, and all the variables

-11y+3(y+4)=0

We multiply parentheses

-11y+3y+12=0

We add all the numbers together, and all the variables

-8y+12=0

We move all terms containing y to the left, all other terms to the right

-8y=-12

y=-12/-8

y=1+1/2

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