3(y+4)=-2(9y-1)+3y

Solution for 3(y+4)=-2(9y-1)+3y equation:

3(y+4)=-2(9y-1)+3y

We move all terms to the left:

3(y+4)-(-2(9y-1)+3y)=0

We multiply parentheses

3y-(-2(9y-1)+3y)+12=0


We calculate terms in parentheses: -(-2(9y-1)+3y), so:

-2(9y-1)+3y

We add all the numbers together, and all the variables

3y-2(9y-1)

We multiply parentheses

3y-18y+2

We add all the numbers together, and all the variables

-15y+2

Back to the equation:

-(-15y+2)


We get rid of parentheses

3y+15y-2+12=0

We add all the numbers together, and all the variables

18y+10=0

We move all terms containing y to the left, all other terms to the right

18y=-10

y=-10/18

y=-5/9