3(y+4)=-2(9y-1)+3y

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Solution for 3(y+4)=-2(9y-1)+3y equation:



3(y+4)=-2(9y-1)+3y
We move all terms to the left:
3(y+4)-(-2(9y-1)+3y)=0
We multiply parentheses
3y-(-2(9y-1)+3y)+12=0
We calculate terms in parentheses: -(-2(9y-1)+3y), so:
-2(9y-1)+3y
We add all the numbers together, and all the variables
3y-2(9y-1)
We multiply parentheses
3y-18y+2
We add all the numbers together, and all the variables
-15y+2
Back to the equation:
-(-15y+2)
We get rid of parentheses
3y+15y-2+12=0
We add all the numbers together, and all the variables
18y+10=0
We move all terms containing y to the left, all other terms to the right
18y=-10
y=-10/18
y=-5/9

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