3(y+4)=-9y-48

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Solution for 3(y+4)=-9y-48 equation: 



3(y+4)=-9y-48

We move all terms to the left:

3(y+4)-(-9y-48)=0

We multiply parentheses

3y-(-9y-48)+12=0

We get rid of parentheses

3y+9y+48+12=0

We add all the numbers together, and all the variables

12y+60=0

We move all terms containing y to the left, all other terms to the right

12y=-60

y=-60/12

y=-5

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